16x^2-96x-640=0

Solution for 16x^2-96x-640=0 equation:

16x^2-96x-640=0

a = 16; b = -96; c = -640;
Δ = b2-4ac
Δ = -962-4·16·(-640)
Δ = 50176
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{50176}=224$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-96)-224}{2*16}=\frac{-128}{32}
=-4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-96)+224}{2*16}=\frac{320}{32}
=10
$